3(2x^2-x+7)-(-x^2-3x+5)=0

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Solution for 3(2x^2-x+7)-(-x^2-3x+5)=0 equation: 



3(2x^2-x+7)-(-x^2-3x+5)=0

We multiply parentheses

-(-x^2-3x+5)+6x^2-3x+21=0

We get rid of parentheses

x^2+6x^2+3x-3x-5+21=0

We add all the numbers together, and all the variables

7x^2+16=0

a = 7; b = 0; c = +16;
Δ = b2-4ac
Δ = 02-4·7·16
Δ = -448
Delta is less than zero, so there is no solution for the equation

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